Programming Test 1: Fizz Buzz

Hopefully I’ve not misinterpreted the challenge here. Count to 100, if the number is divisible by three, output Fizz, if divisible by five, output Buzz.

If its Divisible by 5 and 3, FizzBuzz!

Here’s my solution in node.js:

for (var i=0; i < 100 ; i++)
{
  var ans = "";

  if (divByThree(i)){ans = "fizz"}
  if (divByFive(i)){ans = "buzz"}
  if (divByFive(i) && divByThree(i)) {ans = "fizzbuzz"}
  console.log (i + ": " + ans);

}

function divByThree (num)
 {
   if (parseInt(num) % 3 == 0)
 {
  return true;
 }
 else {
   return false;
  }
}

function divByFive (num)
 {
  if (parseInt(num) % 5 == 0)
 {
 return true;
 }
 else {
  return false;
 }

}